Inverse Trigonometric Functions Question 3
Question: $ \cos [ {{\cos }^{-1}}( \frac{-1}{7} )+{{\sin }^{-1}}( \frac{-1}{7} ) ]= $
[EAMCET 2003]
Options:
A) $ -1/3 $
B) 0
C) $ 1/3 $
D) $ 4/9 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \cos { {{\cos }^{-1}}( \frac{-1}{7} )+{{\sin }^{-1}}( \frac{-1}{7} ) }=\cos \left( \frac{3\pi}{4} \right)=\frac{-\sqrt{2}}{2} $
BETA
