Inverse Trigonometric Functions Question 55

Question: Let $ a,b,c>0 $ and $ x={{\tan }^{-1}}\sqrt{\frac{a}{bc}(a+b+c),} $ $ y={{\tan }^{-1}}\sqrt{\frac{b}{ca}(a+b+c)} $ and $ z={{\tan }^{-1}}\sqrt{\frac{c}{ab}(a+b+c)} $ , then

Options:

A) $ \Sigma \tan x\tan y=1 $

B) $ \Sigma \cot x\cot y=1 $

C) $ \Sigma x=\frac{\pi }{2} $

D) None of these

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Answer:

Correct Answer: B

$ x+y+z=\pi $