Inverse Trigonometric Functions Question 6
Question: The value of $ \tan ( {{\tan }^{-1}}\frac{1}{2}-{{\tan }^{-1}}\frac{1}{3} ) $ is
[AMU 2001]
Options:
A) $ 5/6 $
B) $ 7/6 $
C) $ 1/6 $
D) $ 1/7 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \tan [ {{\tan }^{-1}}\frac{1}{2}-{{\tan }^{-1}}\frac{1}{3} ] $ = $ \tan [ {{\tan }^{-1}}\frac{\frac{1}{2}-\frac{1}{3}}{1+\frac{1}{6}} ] $ = $ \tan {{\tan }^{-1}}( \frac{1}{6}\times \frac{6}{7} ) $ = $ \frac{1}{7} $ .
BETA
