Inverse Trigonometric Functions Question 65
Question: $ {{\cos }^{-1}}\frac{1}{2}+2{{\sin }^{-1}}\frac{1}{2} $ is equal to
[MP PET 1998; UPSEAT 2004]
Options:
A) $ \frac{\pi }{4} $
B) $ \frac{\pi }{6} $
C) $ \frac{\pi }{3} $
D) $ \frac{2\pi }{3} $
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Answer:
Correct Answer: D
Solution:
$ {{\cos }^{-1}}\frac{1}{2}+2{{\sin }^{-1}}\frac{1}{2}=\frac{\pi }{3}+\frac{2\pi }{6}=\frac{2\pi }{3} $ .
BETA
