Inverse Trigonometric Functions Question 78
Question: Two angles of a triangle are $ {{\cot }^{-1}}2 $ and $ {{\cot }^{-1}}3. $ then the third angle is
Options:
A) $ \frac{\pi }{4} $
B) $ \frac{3\pi }{4} $
C) $ \frac{\pi }{6} $
D) $ \frac{\pi }{3} $
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Answer:
Correct Answer: B
The sum of the two given angles is $ {{\cot }^{-1}}(2)+co{t^{-1}}(3)=ta{n^{-1}}( \frac{1}{2} )+{{\tan }^{-1}}( \frac{1}{3} ) $
$ ={{\tan }^{-1}}(1)=\frac{\pi }{4} $ So, the third angle is $ \pi -\frac{\pi }{4}=\frac{3\pi }{4} $
BETA
