Inverse Trigonometric Functions Question 90
Question: The domain of $ {{\sin }^{-1}}x $ is
[Roorkee 1993]
Options:
A) $ (-\pi ,\pi ) $
B) [-1, 1]
C) $ (0,2\pi ) $
D) $ (-\infty ,\infty ) $
Show Answer
Answer:
Correct Answer: B
Solution:
It is obvious.
$ {{\sin }^{-1}}x $ is defined only for $x∈[−1,1]$