Inverse Trigonometric Functions Question 90

Question: The domain of $ {{\sin }^{-1}}x $ is

[Roorkee 1993]

Options:

A) $ (-\pi ,\pi ) $

B) [-1, 1]

C) $ (0,2\pi ) $

D) $ (-\infty ,\infty ) $

Show Answer

Answer:

Correct Answer: B

Solution:

It is obvious.

$ {{\sin }^{-1}}x $ is defined only for $x∈[−1,1]$