Limits Continuity And Differentiability Question 60
Question: Let $ f(x)=[x^{3}-3],[x]= $ G.I.F. Then the no. of points in the interval (1, 2) where function is discontinuous is
Options:
A) 5
B) 4
C) 6
D) 3
Show Answer
Answer:
Correct Answer: C
Solution:
$ f(x)=[x^{3}-3] $
$ {{(1.26)}^{3}}=2-3=-1;{{(1.44)}^{3}}=3-3=0 $
Similarly, we can check for other points where $ f(x) $ changes values to 1, 2, 3, 4.
$ \therefore $ Total number of points of discontinuity are 6.
BETA
