Linear Programming Question 100

Question: Solution of $ \frac{x-7}{x+3}>2 $ is

Options:

A) $ (-3,\infty ) $

B) $ (-\infty ,-13) $

C) (-13, -3)

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ \frac{x-7}{x+3}>2 $

$ \Rightarrow \frac{x-7}{x+3}-2>0 $

$ \Rightarrow \frac{-x-13}{x+3}>0 $

$ \Rightarrow \frac{x+13}{x+3}<0 $

$ \Rightarrow -13<x<-3 $