Linear Programming Question 100
Question: Solution of $ \frac{x-7}{x+3}>2 $ is
Options:
A) $ (-3,\infty ) $
B) $ (-\infty ,-13) $
C) (-13, -3)
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{x-7}{x+3}>2 $
$ \Rightarrow \frac{x-7}{x+3}-2>0 $
$ \Rightarrow \frac{-x-13}{x+3}>0 $
$ \Rightarrow \frac{x+13}{x+3}<0 $
$ \Rightarrow -13<x<-3 $