Linear-Programming Question 136
Question: The true statement for the graph of in equations $ 3x+2y\le 6 $ and $ 6x+4y\ge 20, $ is
Options:
A) Both graph are disjoint
B) Both contain (0, 3)
C) Both contain point (1, 1)
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
[a] The equations, corresponding to inequalities $ 3x+2y\le 6 $ and $ 6x+4y\ge 20, $ are $ 3x+2y=6 $ and $ 6x+4y=20 $ , so the lines represented by these equation are parallel. Hence the graphs are disjoint.
BETA
