Linear-Programming Question 143
Question: The maximum value of $ z=3x+4y $ subject to the condition $ x+y\le 40,x+2y\le 60,x,y\ge 0 $ is
Options:
A) 130
B) 120
C) 40
D) 140
Show Answer
Answer:
Correct Answer: D
Solution:
[d] obviously, $ z=3x+4y $ will be maximum at $ (20,20) $
$ \therefore Maxz=3\times 20+4\times 20=60+80=140 $