Linear-Programming Question 143

Question: The maximum value of $ z=3x+4y $ subject to the condition $ x+y\le 40,x+2y\le 60,x,y\ge 0 $ is

Options:

130

120

40

140

Show Answer

Answer:

Correct Answer: D

Solution:

d obviously, $ z=3x+4y $ will be maximum at $ (0,0) $ $ \therefore Maxz=3\times 20+4\times 20=60+80=140 $

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