Linear-Programming Question 143

Question: The maximum value of $ z=3x+4y $ subject to the condition $ x+y\le 40,x+2y\le 60,x,y\ge 0 $ is

Options:

A) 130

B) 120

C) 40

D) 140

Show Answer

Answer:

Correct Answer: D

Solution:

[d] obviously, $ z=3x+4y $ will be maximum at $ (20,20) $
$ \therefore Maxz=3\times 20+4\times 20=60+80=140 $