Linear Programming Question 29
Question: In equations $ 3x-y\ge 3 $ and $ 4x-y>4 $
[MP PET 2001]
Options:
A) Have a solution for positive x and y
B) Have no solution for positive x and y
C) Has a solution for all x
D) Have a solution for all y
Show Answer
Answer:
Correct Answer: A
Solution:
Following figure will be obtained by drawing the graphs of the given equations.
From $ 3x-y\ge 3,\frac{x}{1}+\frac{y}{-3}=1 $
From $ 4x-y>4,\frac{x}{1}+\frac{y}{-4}=1 $
Clearly the common region of both is true for positive values of (x, y). It is also true for positive value of x and negative value of y.
BETA
