Linear Programming Question 5

Question: In equations $ 3x-y\ge 3 $ and $ 4x-y\ge 4 $

Options:

A) Have solution for positive x and y

B) Have no solution for positive x and y

C) Have solution for all x

D) Have solution for all y

Show Answer

Answer:

Correct Answer: A

Solution:

Following figure will be obtained on drawing the graphs of given in equations.

From $ 3x-y\ge 3, $

$ \Rightarrow \frac{x}{1}+\frac{y}{-3}=1 $

From $ 4x-y\ge 4, $

$ \Rightarrow \frac{x}{1}+\frac{y}{-4}=1 $

Clearly the common region of both is true for positive value of (x, y).