Linear Programming Question 5
Question: In equations $ 3x-y\ge 3 $ and $ 4x-y\ge 4 $
Options:
A) Have solution for positive x and y
B) Have no solution for positive x and y
C) Have solution for all x
D) Have solution for all y
Show Answer
Answer:
Correct Answer: A
Solution:
Following figure will be obtained on drawing the graphs of given in equations.
From $ 3x-y\ge 3, $
$ \Rightarrow \frac{x}{1}+\frac{y}{-3}=1 $
From $ 4x-y\ge 4, $
$ \Rightarrow \frac{x}{1}+\frac{y}{-4}=1 $
Clearly the common region of both is true for positive value of (x, y).