Linear Programming Question 53
Question: A vertex of the linear inequalities $ 2x+3y\le 6 $ , $ x+4y\le 4 $ and $ x,\ y\ge 0 $ , is
Options:
A) (1, 0)
B) (1, 1)
C) $ ( \frac{12}{5},\ \frac{2}{5} ) $
D) $ ( \frac{2}{5},\ \frac{12}{5} ) $
Show Answer
Answer:
Correct Answer: C
Solution:
Solving $ 2x+3y=6 $ and $ x+4y=4 $ , we get $ x=\frac{12}{5},y=\frac{2}{5} $ . Hence a vertex is $ ( \frac{12}{5},\frac{2}{5} ) $ .
BETA
