Linear Programming Question 69
Question: The maximum value of $ \mu =3x+4y $ , subject to the conditions $ x+y\le 40,x+2y\le 60,x,y\ge 0 $ is
[MP PET 2004]
Options:
A) 130
B) 120
C) 40
D) 140
Show Answer
Answer:
Correct Answer: D
Solution:
Obviously, $ \mu =3x+4y $ will be maximum at $ (20,20) $ \ Max $ \mu =3\times 20+4\times 20 $ = $ 60+80=140 $ .
BETA
