Linear Programming Question 69

Question: The maximum value of $ \mu =3x+4y $ , subject to the conditions $ x+y\le 40,x+2y\le 60,x,y\ge 0 $ is

[MP PET 2004]

Options:

130

120

40

140

Show Answer

Answer:

Correct Answer: D

Solution:

Obviously, $ \mu =3x+4y $ will be maximum at $ (20,20) $ \ Max $ \mu =3\times 20+4\times 20 $ = $ 60+80=140 $ .



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