Pair Of Straight Lines Question 111
Question: If the bisectors of angles represented by $ ax^{2}+2hxy+by^{2}=0 $ and $ a’x^{2}+2h’xy+b’y^{2}=0 $ are same, then
Options:
A) $ (a-b)h’=(a’-b’)h $
B) $ (a-b)h=(a’-b’)h’ $
C) $ (a+b)h’=(a’-b’)h $
D) $ (a-b)h’=(a’+b’)h $
Show Answer
Answer:
Correct Answer: A
Solution:
Since bisectors are same, therefore $ \frac{a-b}{h}=\frac{a’-b’}{h’} $
Therefore $ (a-b){h}’=({a}’-{b}’)h $ .
BETA
