Pair Of Straight Lines Question 121
Question: If the lines represented by the equation $ 6x^{2}+41xy-7y^{2}=0 $ make angles $ \alpha $ and $ \beta $ with x-axis, then $ \tan \alpha .\tan \beta $ =
Options:
A) - 6/7
B) 6/ 7
C) 7/6
D) - 7/6
Show Answer
Answer:
Correct Answer: A
Solution:
$ \tan \alpha \tan \beta =m_1m_2=\frac{a}{b}=-\frac{6}{7} $ .
BETA
