A) Coincident
B) Parallel
C) Mutually perpendicular
D) Imaginary
Correct Answer: D
. $ x^{2}+y^{2}+xy=0\Rightarrow (x-\omega y)(x-{{\omega }^{2}}y)=0 $
$ 1,\ \omega ,\ {{\omega }^{2}} $ are cube roots of unity. Hence the lines are imaginary.
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