Pair Of Straight Lines Question 26
The point of intersection of the lines represented by the equation $ 2x^{2}+3y^{2}+7xy+8x+14y+8=0 $ is not defined as the equation represents a conic section, not two intersecting lines.
Options:
A) (0, 2)
B) (1, 2)
C) (-2, 0)
D) (-2, 1)
Show Answer
Answer:
Correct Answer: C
Solution:
If the equation is general equation $ ax^{2}+2hxy+by^{2}+2gx+2fy+c=0 $ .
Then points of intersection are given by $ ( \frac{hf-bg}{ab-h^{2}},\frac{hg-af}{ab-h^{2}} ) $ Hence point is $ (-2,0) $ .
BETA
