Pair Of Straight Lines Question 39
Question: If the point (2,-3) lies on $ kx^{2}-3y^{2}+2x+y-2=0 $ , then k is equal to
Options:
A) $ \frac{1}{7} $
B) 16
C) 7
D) 12
Show Answer
Answer:
Correct Answer: C
Solution:
Point $ (2,-3) $ lies on the line $ kx^{2}-3y^{2}+2x+y-2=0 $
Therefore $ {{(2)}^{2}}k-3{{(-3)}^{2}}+2.2-3-2=0 $
$ 4k-28=0\Rightarrow k=7 $ .
BETA
