Pair Of Straight Lines Question 48
Question: The equation of the lines passing through the origin and parallel to the lines represented by the equation $ 2x^{2}-xy-6y^{2}+7x+21y-15=0 $ , is
Options:
A) $ 2x^{2}-xy-6y^{2}=0 $
B) $ 6x^{2}-xy+2y^{2}=0 $
C) $ 6x^{2}-xy-2y^{2}=0 $
D) $ 2x^{2}+xy-6y^{2}=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
Equation is $ 2x^{2}-xy-6y^{2}+7x+21y-15=0 $
Therefore, equation of lines parallel to given lines and passes through origin is homogeneous 2nd degree equation i.e., $ 2x^{2}-xy-6y^{2}=0. $
BETA
