Pair Of Straight Lines Question 51
Question: Separate equations of lines, for a pair of lines, whose equation is $ x^{2}+xy-12y^{2}=0 $ , are
[Karnataka CET 2001; Pb. CET 2000]
Options:
A) $ x+4y=0 $ and $ x+3y=0 $
B) $ 2x-3y=0 $ and $ x-4y=0 $
C) $ x-6y=0 $ and $ x-3y=0 $
D) $ x+4y=0 $ and $ x-3y=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ x^{2}+xy-12y^{2}=0 $
Therefore $ x^{2}+4xy-3xy-12y^{2}=0 $
Therefore $ (x+4y)(x-3y)=0 $
Therefore separate equations for the lines are $ x+4y=0 $ and $ x-3y=0 $ .
BETA
