Pair Of Straight Lines Question 65

Question: The straight lines joining the origin to the points of intersection of the line $ 2x+y=1 $ and curve $ 3x^{2}+4xy-4x+1=0 $ include an angle

[MP PET 1993]

Options:

A) p/2

B) p/3

C) p/4

D) p/6

Show Answer

Answer:

Correct Answer: A

Solution:

Making equation of curve homogeneous w.r.t. line $ 3x^{2}+4xy-4x(2x+y)+{{(2x+y)}^{2}}=0 $

$ \Rightarrow 3x^{2}+4xy-8x^{2}-4xy+4x^{2}+y^{2}+4xy=0 $

$ \Rightarrow x^{2}-4xy-y^{2}=0 $

Angle between these two lines is $ \tan \theta =\frac{2\sqrt{h^{2}-ab}}{a+b} $

$ =\frac{2\sqrt{4+1}}{0}=\infty $ i.e., lines are perpendicular.