SATHEE: Permutations And Combinations Question 10

Permutations And Combinations Question 10

Question: The number of ways in which 5 male and 2 female members of a committee can be seated around a round table so that the two female are not seated together is [Roorkee 1999]

Options:

A) 480

B) 600

C) 720

D) 840

Show Answer

Answer:

Correct Answer: A

Solution:

Fix up a male and the remaining 4 male can be seated in 4! ways. Now no two female are to sit together and as such the 2 female are to be arranged in five empty seats between two consecutive male and number of arrangement will be $ {}^{5}P_2 $ . Hence by fundamental theorem the total number of ways is = $ 4!\times {}^{5}P_2 $ = 24 × 20 = 480 ways.

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Permutations And Combinations Question 10

Question: The number of ways in which 5 male and 2 female members of a committee can be seated around a round table so that the two female are not seated together is [Roorkee 1999]

Options:

Answer:

Solution:

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