Permutations And Combinations Question 101

Question: In an examination there are three multiple choice questions and each question has 4 choices. Number of ways in which a student can fail to get all answers correct, is [Pb. CET 1990; UPSEAT 2001]

Options:

A) 11

B) 12

C) 27

D) 63

Show Answer

Answer:

Correct Answer: D

Solution:

  • Each question can be answered in 4 ways and all questions can be answered correctly in only one way, so required number of ways $ =4^{3}-1=63 $ .



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