Permutations And Combinations Question 124

Question: Out of 10 white, 9 black and 7 red balls, the number of ways in which selection of one or more balls can be made, is

Options:

A) 881

B) 891

C) 879

D) 892

Show Answer

Answer:

Correct Answer: C

Solution:

  • The required number of ways are $ (10+1)(9+1)(7+1)-1=11\times 10\times 8-1=879 $ .



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