Permutations And Combinations Question 130

Question: The number of ways of dividing 52 cards amongst four players equally, are [IIT 1979]

Options:

A) $ \frac{52\ !}{{{(13\ !)}^{4}}} $

B) $ \frac{52\ !}{{{(13\ !)}^{2}}\ 4\ !} $

C) $ \frac{52\ !}{{{(12\ !)}^{4}}\ (4\ !)} $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

  • Required number of ways $ {{=}^{52}}C _{13}{{\times }^{39}}C _{13}{{\times }^{26}}C _{13}{{\times }^{13}}C _{13} $ $ =\frac{52\ !}{39\ !\ \times 13\ !}\times \frac{39\ !}{26!\ \times 13\ !}\times \frac{26\ !}{13\ !\ \times 13\ !}\times \frac{13\ !}{13\ !}=\frac{52\ !}{{{(13\ !)}^{4}}} $ .



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