Permutations And Combinations Question 134
Question: The number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if at least 1 green and 1 blue ball is to be included [IIT 1974]
Options:
A) 3700
B) 3720
C) 4340
D) None of these
Correct Answer: B At least one green ball can be selected out of 5 green balls in $ 2^{5}-1 $ $ i.e. $ , in 31 ways. Similarly at least one blue ball can be selected from 4 blue balls in $ 2^{4}-1=15 $ ways. And at least one red or not red can be selected in $ (n+1)\ ! $ ways. Hence required number of ways = $ 31\times 15\times 8=3720 $ .
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Answer:
Solution:
BETA
