SATHEE: Permutations And Combinations Question 134

Permutations And Combinations Question 134

Question: The number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if at least 1 green and 1 blue ball is to be included [IIT 1974]

Options:

A) 3700

B) 3720

C) 4340

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

At least one green ball can be selected out of 5 green balls in $ 2^{5}-1 $ $ i.e. $ , in 31 ways. Similarly at least one blue ball can be selected from 4 blue balls in $ 2^{4}-1=15 $ ways. And at least one red or not red can be select in $ (n+1)\ ! $ ways. Hence required number of ways = $ 31\times 15\times 8=3720 $ .

BETA

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Permutations And Combinations Question 134

Question: The number of groups that can be made from 5 different green balls, 4 different blue balls and 3 different red balls, if at least 1 green and 1 blue ball is to be included [IIT 1974]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Mentorship

Menu