Permutations And Combinations Question 140

Question: The number of ways in which 10 persons can go in two boats so that there may be 5 on each boat, supposing that two particular persons will not go in the same boat is [Pb. CET 1999]

Options:

A) $ \frac{1}{2}{{(}^{10}}C_5) $

B) $ 2{{(}^{8}}C_4) $

C) $ \frac{1}{2}{{(}^{8}}C_5) $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • First omit two particular persons, remaining 8 persons may be 4 in each boat. This can be done in $ ^{8}C_4 $ ways. The two particular persons may be placed in two ways one in each boat. Therefore total number of ways are $ =2{{\times }^{8}}C_4 $ .



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें