SATHEE: Permutations And Combinations Question 156

Permutations And Combinations Question 156

Question: A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five question. The number of choices available to him is [AIEEE 2003]

Options:

A) 140

B) 196

C) 280

D) 346

Show Answer

Answer:

Correct Answer: B

Solution:

As for given question two cases are possible. (i) Selecting 4 out of first 5 questions and 6 out of remaining 8 questions $ ={{}^{5}}C_4\times {{}^{8}}C_6=140 $ choices. (ii) Selecting 5 out of first 5 questions and 5 out of remaining 8 questions $ ={{}^{5}}C_5\times {{}^{8}}C_5=56 $ choices. \ Total no. of choices = 140 + 56 = 196.

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Permutations And Combinations Question 156

Question: A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five question. The number of choices available to him is [AIEEE 2003]

Options:

Answer:

Solution:

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