SATHEE: Permutations And Combinations Question 174

Permutations And Combinations Question 174

Question: In how many ways can a team of 11 players be formed out of 25 players, if 6 out of them are always to be included and 5 always to be excluded

Options:

A) 2020

B) 2002

C) 2008

D) 8002

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Since 5 players are always to be excluded and 6 players always to be included, therefore 5 players are to be chosen form 14. Hence. Required number of ways is $ ^{14}C_5 $ =2002.

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Permutations And Combinations Question 174

Question: In how many ways can a team of 11 players be formed out of 25 players, if 6 out of them are always to be included and 5 always to be excluded

Options:

Answer:

Solution:

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