SATHEE: Permutations And Combinations Question 180

Permutations And Combinations Question 180

Question: The number of ways to give 16 different things to three persons A,B,C so that B gets one more than A and C gets two more than B is

Options:

A) $ \frac{16!}{4!5!7!} $

B) $ 4!5!7! $

C) $ \frac{16!}{3!5!8!} $

D) none of these

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Obviously, A, B, and C get 4, 5, and 7 objects, respectively. Then number of distribution ways is equal to number of division of ways, which is given by 16!(4!5!7!).

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Permutations And Combinations Question 180

Question: The number of ways to give 16 different things to three persons A,B,C so that B gets one more than A and C gets two more than B is

Options:

Answer:

Solution:

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