SATHEE: Permutations And Combinations Question 183

Permutations And Combinations Question 183

Question: A man has three friends. The number of ways he can invite one friend every day for dinner on six successive nights so that no friend is invited more than three times is

Options:

A) 640

B) 320

C) 420

D) 510

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Let x, y, z be the friends and a, b, c denote the case when x is now, we have the following possibilities: (a, b, c) = (1, 2, 3) or (3 3 0) or (2 2 2) [grouping of 6 days of week] Hence, the total number of ways is $ \frac{6!}{1!2!3!}3!+\frac{6!}{3!3!2!}3!+\frac{6!}{(2!2!2!)}3! $

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Permutations And Combinations Question 183

Question: A man has three friends. The number of ways he can invite one friend every day for dinner on six successive nights so that no friend is invited more than three times is

Options:

Answer:

Solution:

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