SATHEE: Permutations And Combinations Question 192

Permutations And Combinations Question 192

Question: The number of divisors of 9600 including 1 and 9600 are [IIT Screening 1993]

Options:

A) 60

B) 58

C) 48

D) 46

Show Answer

Answer:

Correct Answer: C

Solution:

Since $ 9600=2^{7}\times 3\times 5^{2} $ Hence, number of divisors $ =(7+1)(1+1)(2+1)=48 $ .

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Permutations And Combinations Question 192

Question: The number of divisors of 9600 including 1 and 9600 are [IIT Screening 1993]

Options:

Answer:

Solution:

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