SATHEE: Permutations And Combinations Question 198

Permutations And Combinations Question 198

Question: Number of divisors of $ n=38808 $ (except 1 and n) is [RPET 2000]

Options:

A) 70

B) 68

C) 72

D) 74

Show Answer

Answer:

Correct Answer: A

Solution:

Since, 38808 = 8 × 4851 $ =8\times 9\times 539=8\times 9\times 7\times 7\times 11=2^{3}\times 3^{2}\times 7^{2}\times 11 $ So, number of divisors = (3 + 1) (2 + 1) (2 + 1) (1 + 1) = 72. This includes two divisors 1 and 38808. Hence, the required number of divisors = 72 - 2 = 70.

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Permutations And Combinations Question 198

Question: Number of divisors of $ n=38808 $ (except 1 and n) is [RPET 2000]

Options:

Answer:

Solution:

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