SATHEE: Permutations And Combinations Question 199

Permutations And Combinations Question 199

Question: If $ ^{n}P_4=24.{{}^{n}}C_5, $ then the value of n is [Karnataka CET 2001]

Options:

A) 10

B) 15

C) 9

D) 5

Show Answer

Answer:

Correct Answer: C

Solution:

Given, $ ^{n}P_4=24.{{}^{n}}C_5. $ Therefore, $ n(n-1)(n-2)(n-3) $ $ =24\times \frac{n(n-1)(n-2)(n-3)(n-4)}{5.4.3.2.1} $

$ \Rightarrow $ $ 1=\frac{(n-4)}{5} $
Þ $ n-4=5 $
Þ $ n=9 $ .

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Permutations And Combinations Question 199

Question: If $ ^{n}P_4=24.{{}^{n}}C_5, $ then the value of n is [Karnataka CET 2001]

Options:

Answer:

Solution:

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