SATHEE: Permutations And Combinations Question 203

Permutations And Combinations Question 203

The number of ways to sit 3 men and 2 women in a bus such that the total number of sitted men and women on each side is 3 [DCE 2005]

Options:

A) 5!

B) $ ^{6}C_5\times 5! $

C) $ 6! \times {}^{6}P_5 $

D) $ 5! + {}^{6}C_5 $

Show Answer

Answer:

Correct Answer: B

Solution:

3 men and 2 women equal to 5. A group of 5 members make 5! permutations with each other. \ The number of ways to sit 5 members = 5! 6 Places are filled by 5 members by $ ^{6}C_5 $ ways \ The total number of ways to sit 5 members on 6 seats of a bus = $ ^{6}C_5\times 5! $ .

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Permutations And Combinations Question 203

The number of ways to sit 3 men and 2 women in a bus such that the total number of sitted men and women on each side is 3 [DCE 2005]

Options:

Answer:

Solution:

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