Permutations And Combinations Question 237

Question: How many numbers divisible by 5 and lying between 3000 and 4000 can be formed from the digits 1, 2, 3, 4, 5, 6 (repetition is not allowed)

Options:

A) $ \frac{n+r-1}{r} $

B) $ ^{5}P_2 $

C) $ ^{4}P_2 $

D) $ ^{6}P_3 $

Show Answer

Answer:

Correct Answer: C

Solution:

  • To be divisible by 5, the digit 5 must be at unit place, so now to be between 3000 and 4000, 3 must be at thousand place. Hence the required number of ways $ ={{}^{4}}P_2 $ .