Permutations And Combinations Question 239

Question: How many numbers can be formed from the digits 1, 2, 3, 4 when the repetition is not allowed

Options:

A) $ ^{4}P_4 $

B) $ ^{4}P_3 $

C) $ ^{4}P_1{{+}^{4}}P_2{{+}^{4}}P_3 $

D) $ ^{4}P_1{{+}^{4}}P_2{{+}^{4}}P_3{{+}^{4}}P_4 $

Show Answer

Answer:

Correct Answer: D

Solution:

  • Number of 1 digit numbers $ {{=}^{4}}P_1 $ Number of 2 digit numbers $ {{=}^{4}}P_2 $ Number of 3 digit numbers $ {{=}^{4}}P_3 $ Number of 4 digit numbers $ {{=}^{4}}P_4 $ Hence the required number of ways $ {{=}^{4}}P_1{{+}^{4}}P_2{{+}^{4}}P_3{{+}^{4}}P_4 $ .