Permutations And Combinations Question 247
Question: How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition is not allowed)
Options:
A) 224
B) 280
C) 324
D) None of these
Correct Answer: A The number will be even if last digit is 2, 4, 6 or 8 i.e., the last digit can be filled in 4 ways and remaining two digits can be filled in $ ^{9}P_2 $ ways. Hence required number of numbers are $ ^{9}P_2\times 4= 432 $ .
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Answer:
Solution:
BETA
