SATHEE: Permutations And Combinations Question 247

Permutations And Combinations Question 247

Question: How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition is not allowed)

Options:

A) 224

B) 280

C) 324

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

The number will be even if last digit is 2, 4, 6 or 8 i.e., the last digit can be filled in 4 ways and remaining two digits can be filled in $ ^{8}P_2 $ ways. Hence required number of numbers are $ ^{8}P_2\times 4=224 $ .

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Permutations And Combinations Question 247

Question: How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition is not allowed)

Options:

Answer:

Solution:

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