Permutations And Combinations Question 249
Question: The value of $ ^{n}P _{r} $ is equal to [IIT 1971; MP PET 1993]
Options:
A) $ ^{n-1}P _{r}+r{{}^{n-1}}{P _{r-1}} $
B) $ n.{{\ }^{n-1}}P _{r}{{+}^{n-1}}{P _{r-1}} $
C) $ n{{(}^{n-1}}P _{r}{{+}^{n-1}}{P _{r-1}}) $
D)  $ ^{n-1}{P _{r-1}}{{+}^{n-1}}P _{r} $
 Correct Answer: AShow Answer
  Answer:
Solution:
Þ  $ \frac{^{n-1}P _{r}}{r!}+\frac{^{n-1}{P _{r-1}}}{(r-1)!}=\frac{^{n}P _{r}}{r!} $
Þ  $ ^{n-1}P _{r}+r.{{}^{n-1}}{P _{r-1}}={{}^{n}}P _{r} $ .
 BETA
  BETA 
             
             
           
           
           
          