SATHEE: Permutations And Combinations Question 259

Permutations And Combinations Question 259

Question: In how many ways can 10 balls be divided between two boys, one receiving two and the other eight balls

Options:

A) 45

B) 75

C) 90

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ A $ gets 2, $ B $ gets 8; $ \frac{10\ !}{2\ !\ 8\ !}=45 $ $ A $ gets 8, $ B $ gets 2; $ \frac{10\ !}{8\ !\ 2\ !}=45 $

$ \therefore $ $ 45+45=90 $ .

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Permutations And Combinations Question 259

Question: In how many ways can 10 balls be divided between two boys, one receiving two and the other eight balls

Options:

Answer:

Solution:

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