Permutations And Combinations Question 26
Question: A five digit number divisible by 3 has to formed using the numerals 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways in which this can be done is [IIT 1989; AIEEE 2002]
Options:
A) 216
B) 240
C) 600
D) 3125
Correct Answer: A
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Answer:
Solution:
$ \therefore $ The total number of such 5 digit number $ ={{}^{5}}P_5+{{(}^{5}}P_5{{-}^{4}}P_4)=120+96=216 $ .
BETA
