SATHEE: Permutations And Combinations Question 274

Permutations And Combinations Question 274

Question: In how many ways can 5 boys and 3 girls sit in a row so that no two girls are together

Options:

A) $ 5!\times 3! $

B) $ ^{4}P_3\times 5! $

C) $ ^{6}P_3\times 5! $

D) $ ^{5}P_3\times 3! $

Show Answer

Answer:

Correct Answer: C

Solution:

Since the 5 boys can sit in $ 5\ ! $ ways. In this case there are 6 places are vacant in which the girls can sit in $ ^{6}P_3 $ ways. Therefore required number of ways are $ ^{6}P_3\times 5\ ! $ .

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Permutations And Combinations Question 274

Question: In how many ways can 5 boys and 3 girls sit in a row so that no two girls are together

Options:

Answer:

Solution:

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