SATHEE: Permutations And Combinations Question 278

Permutations And Combinations Question 278

Question: How many numbers consisting of 5 digits can be formed in which the digits 3, 4 and 7 are used only once and the digit 5 is used twice

Options:

A) 30

B) 60

C) 45

D) 90

Show Answer

Answer:

Correct Answer: B

Solution:

Required number of ways are $ \frac{5!}{2!}=60 $ .

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Permutations And Combinations Question 278

Question: How many numbers consisting of 5 digits can be formed in which the digits 3, 4 and 7 are used only once and the digit 5 is used twice

Options:

Answer:

Solution:

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