SATHEE: Permutations And Combinations Question 292

Permutations And Combinations Question 292

Question: In how many ways can 5 boys and 5 girls stand in a row so that no two girls may be together [RPET 1997]

Options:

A) $ {{(5\ !)}^{2}} $

B) $ 5\ !\ \times 4\ ! $

C) $ 5\ !\ \times 6\ ! $

D) $ 6\times 5\ ! $

Show Answer

Answer:

Correct Answer: C

Solution:

5 boys can be stand in a row $ 5\ ! $ ways Now, two girls can’t stand in a row together in $ ^{6}P_5 $ ways. Total no. of required arrangement $ =5\ !\ {{\times }^{6}}P_5=5\ !\ \times 6\ ! $ .

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Permutations And Combinations Question 292

Question: In how many ways can 5 boys and 5 girls stand in a row so that no two girls may be together [RPET 1997]

Options:

Answer:

Solution:

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