Permutations And Combinations Question 302

Question: The number of ways in which 5 boys and 3 girls can be seated in a row so that each girl in between two boys [Kerala (Engg.) 2002]

Options:

A) 2880

B) 1880

C) 3800

D) 2800

Show Answer

Answer:

Correct Answer: A

Solution:

  • First, we seat 5 boys, which can be done in 5! ways B × B × B × B × B. Three girls can be seated in places marked ?×? in $ ^{4}P_3 $ ways. \ Total ways = $ 5!{{.}^{4}}P_3=2880. $

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