There are 10 bags $ B_1,B_2,B_3,…,B_{10}, $ which contain 21, 22, …, 30 different articles respectively. The total number of ways to bring out 10 articles from a bag is
Options:
A) $ ^{31}C _{20}{{-}^{21}}C _{10} $
B) $ ^{31}C _{17} $
C) $ ^{31}C _{11} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- [a] The required number of ways $ {{=}^{21}}C _{10}{{+}^{22}}C _{10}{{+}^{23}}C _{10}+…{{+}^{30}}C _{10} $ $ ={{(}^{21}}C _{10}{{+}^{21}}C _{11}{{+}^{22}}C _{12}{{+}^{23}}C _{13}+…{{+}^{30}}C _{20}){{-}^{21}}C _{11} $ $ {{=}^{22}}C _{11}{{+}^{22}}C _{12}{{+}^{23}}C _{13}+…{{+}^{30}}C _{20}{{-}^{21}}C _{10} $ $ ({{\because }^{n}}{C _{r-1}}{{+}^{n}}C _{r}{{=}^{n+1}}C _{r}) $ $ {{=}^{31}}C _{20}{{-}^{21}}C _{10}. $