SATHEE: Permutations And Combinations Question 330

Permutations And Combinations Question 330

Question: In how many ways a team of 11 players can be formed out of 25 players, if 6 out of them are always to be included and 5 are always to be excluded?

Options:

A) 2020

B) 2002

C) 2008

D) 8002

Show Answer

Answer:

Correct Answer: B

Solution:

[b] As 5 are always to be excluded and 6 always to be included, 5 players to be chosen form 14. Hence, required number of ways are $ ^{14}C_5=2002. $

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Permutations And Combinations Question 330

Question: In how many ways a team of 11 players can be formed out of 25 players, if 6 out of them are always to be included and 5 are always to be excluded?

Options:

Answer:

Solution:

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