Permutations And Combinations Question 333

Question: There are 10 points in a plane, no three are collinear, except 4 which are collinear. All points are joined. Let L be the number of different straight lines and T be the number of different triangles, then

Options:

A) $ T=120 $

B) $ L=40 $

C) $ T=3L-5 $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • [b] $ L{{=}^{10}}C_2{{-}^{4}}C_2+1=45-6+1=40 $ $ T{{=}^{10}}C_3{{-}^{4}}C_3=120-4=3L-4 $