Permutations And Combinations Question 336
Question: A person invites a party of 10 friends at dinner and place them so that 4 are on one round table and 6 on the other round table. The number of ways in which he can arrange the guests is
Options:
A) $ \frac{(10)!}{6!} $
B) $ \frac{(10)!}{24} $
C) $ \frac{(9)!}{24} $
D) None of these
Correct Answer: B
Show Answer
Answer:
Solution:
BETA
